12j^2+40y=7

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Solution for 12j^2+40y=7 equation:


Simplifying
12j2 + 40y = 7

Solving
12j2 + 40y = 7

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-40y' to each side of the equation.
12j2 + 40y + -40y = 7 + -40y

Combine like terms: 40y + -40y = 0
12j2 + 0 = 7 + -40y
12j2 = 7 + -40y

Divide each side by '12'.
j2 = 0.5833333333 + -3.333333333y

Simplifying
j2 = 0.5833333333 + -3.333333333y

Reorder the terms:
-0.5833333333 + j2 + 3.333333333y = 0.5833333333 + -3.333333333y + -0.5833333333 + 3.333333333y

Reorder the terms:
-0.5833333333 + j2 + 3.333333333y = 0.5833333333 + -0.5833333333 + -3.333333333y + 3.333333333y

Combine like terms: 0.5833333333 + -0.5833333333 = 0.0000000000
-0.5833333333 + j2 + 3.333333333y = 0.0000000000 + -3.333333333y + 3.333333333y
-0.5833333333 + j2 + 3.333333333y = -3.333333333y + 3.333333333y

Combine like terms: -3.333333333y + 3.333333333y = 0.000000000
-0.5833333333 + j2 + 3.333333333y = 0.000000000

The solution to this equation could not be determined.

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